Sort a List of 20 Names
The user enters 20 names (or whatever) into an array and the program outputs the 20 inputs alphabetically. The program also stops and sorts what the user has entered so far if the user does not enter anything.
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Codice sorgente
/* By Dfuse
http://dfuse.netfirms.com
molsoncanadians@hotmail.com
*/
#include<iostream.h>
#include <string.h>
void getName(char* name)
{ cout<<"Enter a Name: ";
cin.getline(name, 20, '\n');
if(strlen(name)==19)
cin.ignore(100,'\n');
} //getName
readAllNames(char list [] [20])
{ int i=0;
getName(list[i]);
while((i<19)&&(strlen(list[i])>0))
{ i++;
getName(list[i]);
} //while
return i+1;
}//readAllNames
void printAll(char list[][20],int c)
{ for (int i=0;i<c;i++)
cout<<list[i]<<"\n";
} //printAll
void swap(char *s1, char *s2)
{char* temp;
strcpy(temp,s1);
strcpy(s1,s2);
strcpy(s2,temp);
} //swap
sort(char list[][20], int n)
{ int i, smallPos, pass;
char temp;
for (pass=0; pass<n; pass++)
{ smallPos = pass;
for (i=pass; i<n; i++)
{ if (stricmp (list[i], list[smallPos])< 0)
smallPos = i;
} //for
swap(list[smallPos], list[pass]);
} //for
return;
}
main()
{ char names[20][20];
int count=0;
count=readAllNames(names);
//cout<<"Count= "<<count<<"\n";
sort(names,count);
printAll(names,count);
return 0;
} //main
Commenti originali (3)
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