ExtractFileName
It extracts a filename from a filepath.
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Código fonte
Public Function ExtractFileName(ByVal strPath As String) As String ' StrReverse is only working in VB6 strPath = StrReverse(strPath) strPath = Left(strPath, InStr(strPath, "\") - 1) ExtractFileName = StrReverse(strPath) End Function
Comentários originais (3)
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